Matematika Sekolah Menengah Atas Q. spesial 2 jwbn terverif
8!!! + 7 =
7!! - 9 =
f(x) = 7x + 8!!! - 4
f(3) =

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Q. spesial 2 jwbn terverif
8!!! + 7 =
7!! - 9 =
f(x) = 7x + 8!!! - 4
f(3) =

PAKE CARA
NO NGASAL
NO COPY PASTE
GOOD LUCK

no 1 :

8!!!

= 8 × 5 × 2 × 1

= 40 × 2 × 1

= 80 × 1

= 80

jawab :

= 8!!! + 7

= 80 + 7

= 87

no 2 :

7!!

= 7 × 5 × 3 × 1

= 35 × 3 × 1

= 105

jawab :

= 7!! + 9

= 105 - 9

= 96

no 3 :

8!!!

= 8 × 5 × 2 × 1

= 40 × 2 × 1

= 80 × 1

= 80

penyelesaian :

f(x) = 7x + 8 !!! - 4

f(3) = 7(3) + 80 - 4

f(3) = ( 7 × 3 ) + 80 - 4

f(3) = 21 + 80 - 4

f(3) = 101 - 4

f(3) = 97

#koreksi

Penyelesaian soal :

[tex] \tt 8!!! + 7 [/tex]

[tex] \tt = (8 \times 5 \times 2) + 7 [/tex]

[tex] \tt = (40 \times 2) + 7 [/tex]

[tex] \tt = 80 + 7 [/tex]

[tex] \tt = 87[/tex]

[tex] \\ [/tex]

[tex] \tt 7!! - 9[/tex]

[tex] \tt = (7 \times 5 \times 3 \times 1) - 9[/tex]

[tex] \tt = (35\times 3 \times 1) - 9[/tex]

[tex] \tt = (105 \times 1) - 9[/tex]

[tex] \tt = 105 - 9[/tex]

[tex] \tt = 96[/tex]

[tex] \\ [/tex]

[tex] \tt f(x) = 7x + 8!!! - 4 [/tex]

[tex] \tt f(3) = 7x + 8!!! - 4 [/tex]

[tex] \tt = 7(3)+ 8!!! - 4 [/tex]

[tex] \tt =(7 \times 3)+ 8!!! - 4 [/tex]

[tex] \tt =21+ 8!!! - 4 [/tex]

[tex] \tt =21+ (8 \times 5 \times 2) - 4 [/tex]

[tex] \tt =21+ (40 \times 2) - 4 [/tex]

[tex] \tt =21+ 80 - 4 [/tex]

[tex] \tt = 101 - 4 [/tex]

[tex] \tt = 97[/tex]

[tex] \\ [/tex]

Tysm!

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